Question :
Sum of two vectors A and B is equal to A. Difference of these two vectors is equal to 2A. If A=4 find the MAGNITUDE of vector B.
a)3√2
b)6√2
c)2√6
d)3√6
Question of GIKI test 2012.
Solution:
In terms of rectangular components we can write:
A =√ A2x + A2y
B=√ B2x + B2y
Given:
A + B = A
it means
√( A2x + A2y ) + √( B2x + B2y ) = 4
Squaring Both sides, we get
A2x + A2y + B2x + B2y + 2√( A2x + A2y )( B2x + B2y ) = 16 (equation i)
Also
A-B = 2A
A-B = 8
√( A2x + A2y ) - √( B2x + B2y ) = 8
Squaring Both sides, we get
A2x + A2y + B2x + B2y - 2√( A2x + A2y )( B2x + B2y ) = 64 (equation ii)
Adding equation i and ii we get
2( A2x + A2y + B2x + B2y ) = 80
16 + B2x + B2y = 40
B2x + B2y = 24
B2 = 24
B = √24 = √4x6 = 2√6
Solution:
In terms of rectangular components we can write:
A =√ A2x + A2y
B=√ B2x + B2y
Given:
A + B = A
it means
√( A2x + A2y ) + √( B2x + B2y ) = 4
Squaring Both sides, we get
A2x + A2y + B2x + B2y + 2√( A2x + A2y )( B2x + B2y ) = 16 (equation i)
Also
A-B = 2A
A-B = 8
√( A2x + A2y ) - √( B2x + B2y ) = 8
Squaring Both sides, we get
A2x + A2y + B2x + B2y - 2√( A2x + A2y )( B2x + B2y ) = 64 (equation ii)
Adding equation i and ii we get
2( A2x + A2y + B2x + B2y ) = 80
16 + B2x + B2y = 40
B2x + B2y = 24
B2 = 24
B = √24 = √4x6 = 2√6
what the hell was that? :O
ReplyDelete@ayesha this was one of the question which was in test of GIKI last year :D
ReplyDeleteand this is the hardest and worst thing one would ever wish to see, if the test goes this way, we shouldnt even bother about studying for it because its already a fail fail attempt
ReplyDeletewell in Giki u have to face the questions like these . It will be teh hardest test u'll ever see . The way to get through this test is to clear ur concepts..
ReplyDeleteu substituted 16 but why ?
ReplyDeletein last part of the question ?
magnitude of A is equal to 16 .
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WE are supposed solve it in a minute?
ReplyDeletewe are supposed to solve it in a minute?
ReplyDeleteI have found a short method for this as well. Will add that too.
ReplyDelete